Variance, standard deviation and mean deviationMedium

Variance and Mean of Transformed Observations

Let x₁, x₂,......x₁₀ be ten observations such that $\sum\limits_{i = 1}^{10} {\left( {{x_i} - 2} \right) = 30}$ , $\sum\limits_{i = 1}^{10} {{{\left( {{x_i} - \beta } \right)}^2} = 98}$ , β > 2 and their variance is $\frac{4}{5}$ . If μ and σ²are respectively the mean and the variance of 2(x₁–1) + 4β, 2(x₂–1) + 4β, ....., 2(x₁₀– 1) + 4β, then $\frac{{\beta \mu }}{{{\sigma ^2}}}$ is equal to :

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