Twice Differentiable Function Properties (Jee M… | ExamDuo
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Application of Derivates
Hard
Twice Differentiable Function Properties
Let
g
:
R
→
R
be a non constant twice differentiable such that
g
′
(
1
2
)
=
g
′
(
3
2
)
. If a real valued function
f
is defined as
f
(
x
)
=
1
2
[
g
(
x
)
+
g
(
2
−
x
)
]
, then
Ask about this question
SELECT ONE OPTION
A
f
′
(
x
)
=
0
for atleast two
x
in
(
0
,
2
)
B
f
′
′
(
x
)
=
0
for exactly one
x
in
(
0
,
1
)
C
f
′
(
x
)
=
0
for no
x
in
(
0
,
1
)
D
f
′
(
3
2
)
+
f
′
(
1
2
)
=
1
Check