Telescoping Series Maximum Value (Jee Mains) | ExamDuo
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Telescoping Series Maximum Value
If
1
(
20
−
a
)
(
40
−
a
)
+
1
(
40
−
a
)
(
60
−
a
)
+
.
.
.
+
1
(
180
−
a
)
(
200
−
a
)
=
1
256
, then the maximum value of
a
is :
Ask about this question
SELECT ONE OPTION
A
198
B
202
C
212
D
218
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