Let z1,z2∈Cz_{1}, z_{2} \in Cz1,z2∈C be the distinct solutions of the equation z2+4z−(1+12i)=0z^{2}+4z-(1+12i)=0z2+4z−(1+12i)=0. Then ∣z1∣2+∣z2∣2|z_{1}|^{2}+|z_{2}|^{2}∣z1∣2+∣z2∣2 is equal to :
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