In sulphur estimation, 2.0×10−3 mol2.0 \times 10^{-3} \, \mathrm{mol}2.0×10−3mol of an organic compound (X) (molar mass 76 g mol−176 \, \mathrm{g} \, \mathrm{mol}^{-1}76gmol−1) gave 0.4813 g of barium sulphate (molar mass 233 g mol−1233 \, \mathrm{g} \, \mathrm{mol}^{-1}233gmol−1). The percentage of sulphur in the compound (X) is _____ ×10−1%\times 10^{-1} \%×10−1%. (Nearest integer).