Solving DE with Initial Condition (Jee Mains) | ExamDuo
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First Order Differential Equations
Medium
Solving DE with Initial Condition
Let
y
=
y
(
x
)
be the solution of the differential equation
d
y
d
x
+
y
tan
x
=
2
x
+
x
2
tan
x
,
x
∊
(
−
π
2
,
π
2
)
such that if
y
(
0
)
=
1
,then
Ask about this question
SELECT ONE OPTION
A
y
′
(
π
4
)
−
y
′
(
−
π
4
)
=
π
−
√
2
B
y
(
π
4
)
−
y
(
−
π
4
)
=
√
2
C
y
(
π
4
)
+
y
(
−
π
4
)
=
π
2
2
+
√
2
D
y
′
(
π
4
)
+
y
′
(
−
π
4
)
=
−
√
2
Check