Solving DE Evaluating Expression (Jee Mains) | ExamDuo
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First Order Differential Equations
Medium
Solving DE Evaluating Expression
If
y
=
y
(
x
)
is the solution of the differential equation
(
1
+
e
2
x
)
d
y
d
x
+
2
(
1
+
y
2
)
e
x
=
0
and
y
(
0
)
=
0
then
6
(
y
′
(
0
)
+
(
y
(
log
e
√
3
)
)
2
)
is equal to
Ask about this question
SELECT ONE OPTION
A
2
B
−
2
C
−
4
D
−
1
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