Solving a Separable Differential Equation (Jee … | ExamDuo
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First Order Differential Equations
Medium
Solving a Separable Differential Equation
The solution curve of the differential equation,
(
1
+
e
−
x
)
(
1
+
y
2
)
d
y
d
x
=
y
2
,
which passesthrough the point
(
0
,
1
)
,
is :
Ask about this question
SELECT ONE OPTION
A
y
2
=
1
+
y
log
e
(
1
+
e
x
2
)
B
y
2
+
1
=
y
(
log
e
(
1
+
e
x
2
)
+
2
)
C
y
2
=
1
+
y
log
e
(
1
+
e
−
x
2
)
D
y
2
+
1
=
y
(
log
e
(
1
+
e
−
x
2
)
+
2
)
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