Solving a Differential Equation with Initial Co… | ExamDuo
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First Order Differential Equations
Hard
Solving a Differential Equation with Initial Condition
Let
y
=
y
(
x
)
be the solution of the differential equation
x
(
1
−
x
2
)
d
y
d
x
+
(
3
x
2
y
−
y
−
4
x
3
)
=
0
,
x
>
1
, with
y
(
2
)
=
−
2
. Then
y
(
3
)
is equal to
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SELECT ONE OPTION
A
−
18
B
−
12
C
−
6
D
−
3
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