Solve Differential Equation Initial Condition V… | ExamDuo
Ask Doubts
Log in
First Order Differential Equations
Medium
Solve Differential Equation Initial Condition Value
Let
y
=
y
(
x
)
be the solution of the differential equation
cosec
2
x
d
y
+
2
d
x
=
(
1
+
y
cos
2
x
)
cosec
2
x
d
x
, with
y
(
π
4
)
=
0
.
Then, the value of
(
y
(
0
)
+
1
)
2
is equal to:
Ask about this question
SELECT ONE OPTION
A
e
1
∕
2
B
e
−
1
∕
2
C
e
−
1
D
e
Check