Solve DE with Initial Condition (Jee Mains) | ExamDuo
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First Order Differential Equations
Medium
Solve DE with Initial Condition
Let the solution curve of the differential equation
x
d
y
d
x
−
y
=
√
y
2
+
16
x
2
,
y
(
1
)
=
3
be
y
=
y
(
x
)
. Then
y
(
2
)
is equal to:
Ask about this question
SELECT ONE OPTION
A
15
B
11
C
13
D
17
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