Piecewise Function and Absolute Value (Jee Mains) | ExamDuo
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Continuity and Differentiability
Medium
Piecewise Function and Absolute Value
Let f (x) =
{
−
1
−
2
≤
x
<
0
x
2
−
1
0
≤
x
≤
2
and
g (x) = |f (x)| + f (|x|) .
Then, in the interval (–2, 2), g is :-
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SELECT ONE OPTION
A
differentiable at all points
B
not differentiable at two points
C
not continuous
D
not differentiable at one point
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