Permutations with Consecutive Integers

Let b1b2b3b4 be a 4-element permutation with bi∈{1,2,3,.......,100} for 1≤i≤4 and bi≠bj for i≠j, such that either b1,b2, b3 are consecutive integers or b2,b3,b4 are consecutive integers. Then the number of such permutations b1b2b3b4 is equal to___