Parametric Equations Second Derivative (Jee Mains) | ExamDuo
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Chain Rule and Composite Functions
Medium
Parametric Equations Second Derivative
Let
x
(
t
)
=
2
√
2
cos
t
√
s
i
n
2
t
and
y
(
t
)
=
2
√
2
s
i
n
t
√
s
i
n
2
t
,
t
∈
(
0
,
π
2
)
Then
1
+
(
d
y
d
x
)
2
d
2
y
d
x
2
at
t
=
π
4
is equal to:
Ask about this question
SELECT ONE OPTION
A
−
2
√
2
3
B
2
3
C
1
3
D
−
2
3
Check