Min Value Differential Equation Solution (Jee M… | ExamDuo
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First Order Differential Equations
Medium
Min Value Differential Equation Solution
Let
y
=
y
(
x
)
be the solution of the differentialequation
d
y
d
x
=
1
+
x
e
y
−
x
,
−
√
2
<
x
<
√
2
,
y
(
0
)
=
0
then, the minimum value of
y
(
x
)
,
x
∈
(
−
√
2
,
√
2
)
is equal to:
Ask about this question
SELECT ONE OPTION
A
(
1
+
√
3
)
−
log
e
(
√
3
−
1
)
B
(
2
−
√
3
)
−
log
e
2
C
(
2
+
√
3
)
+
log
e
2
D
(
1
−
√
3
)
−
log
e
(
√
3
−
1
)
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