Metal Sulfide Precipitation pH (Jee Mains)

pH, Buffer & Solubility

Hard

Metal Sulfide Precipitation pH

Consider two Group IV metal ions X²⁺ and Y²⁺.
A solution containing 0.01 MX²⁺ and 0.01 MY²⁺ is saturated with H₂S. The pH at which the metal sulphide YS will form as a precipitate is ______ (Nearest integer)
(Given : ${K_{sp}}\left( {XS} \right) = 1 \times {10^{ - 22}}\,at\,{25^o}C,\,\,{K_{sp}}\left( {YS} \right) = 4 \times {10^{ - 16}}\,\,at\,{25^o}\,C,$
[H₂S] = 0.1M in solution, K_a1 × K_a2 (H₂S) = 1.0 × 10^–21, log 2 = 0.30, log 3 = 0.48, log 5 = 0.70)

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