Let A=[10002030−1]A=\begin{bmatrix}1&0&0\\0&2&0\\3&0&-1\end{bmatrix}A=10302000−1 satisfy A20+αA19+βA=[100040001]A^{20}+\alpha A^{19}+\beta A=\begin{bmatrix}1&0&0\\0&4&0\\0&0&1\end{bmatrix}A20+αA19+βA=100040001 for some real numbers α\alphaα and β\betaβ. Then β−α\beta-\alphaβ−α is equal to ______.