Logarithmic Summation Base Value (Jee Mains) | ExamDuo
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Logarithmic Summation Base Value
Let
S
n
(
x
)
=
log
a
1
/
2
x
+
log
a
1
/
3
x
+
log
a
1
/
6
x
+
log
a
1
/
11
x
+
log
a
1
/
18
x
+
log
a
1
/
27
x
+
.
.
.
up to
n
-terms, where
a
>
1
. If
S
24
(
x
)
=
1093
and
S
12
(
2
x
)
=
265
, then value of
a
is equal to
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