Locus of Intersection Point (Jee Mains) | ExamDuo
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Equation & Position in Circle
Medium
Locus of Intersection Point
Let PQ and MN be two straight lines touching the circle x
2
+ y
2
– 4x – 6y – 3 = 0 at the points A and B respectively. Let O be the centre of the circle and ∠AOB = π/3. Then the locus of the point of intersection of the lines PQ and MN is :
SELECT ONE OPTION
A
3(x
2
+ y
2
) – 18x – 12y + 25 = 0
B
x
2
+ y
2
– 12x – 18y – 25 = 0
C
x
2
+ y
2
– 18x – 12y – 25 = 0
D
3(x
2
+ y
2
) – 12x – 18y – 25 = 0
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