Indefinite Integral with Initial Condition (Jee… | ExamDuo
Ask Doubts
Log in
Basics and Substitution
Medium
Indefinite Integral with Initial Condition
Let
I
(
x
)
=
∫
6
s
i
n
2
x
(
1
−
cot
x
)
2
dx
. If
I
(
0
)
=
3
, then
I
(
π
12
)
is equal to :
Ask about this question
SELECT ONE OPTION
A
√
3
B
3
√
3
C
6
√
3
D
2
√
3
Check