Hyperbola Eccentricity Latus Rectum (Jee Mains)

Hyperbola

Medium

Hyperbola Eccentricity Latus Rectum

Let one focus of the hyperbola H : $\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$ be at $\left( {\sqrt {10} ,0} \right)$ and the corresponding directrix be $x = \frac{9}{{\sqrt {10} }}$
If e and l respectively are the eccentricity and the length of the latus rectum of H, then 9 (e² + l) is equal to:

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