General Solution of Differential Equation (Jee … | ExamDuo
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First Order Differential Equations
Medium
General Solution of Differential Equation
The general solution of the differential equation
√
1
+
x
2
+
y
2
+
x
2
y
2
+
x
y
d
y
d
x
=
0
is (where
C
is a constant of integration)
SELECT ONE OPTION
A
√
1
+
y
2
+
√
1
+
x
2
=
1
2
log
e
(
√
1
+
x
2
+
1
√
1
+
x
2
−
1
)
+
C
B
√
1
+
y
2
−
√
1
+
x
2
=
1
2
log
e
(
√
1
+
x
2
+
1
√
1
+
x
2
−
1
)
+
C
C
√
1
+
y
2
+
√
1
+
x
2
=
1
2
log
e
(
√
1
+
x
2
−
1
√
1
+
x
2
+
1
)
+
C
D
√
1
+
y
2
−
√
1
+
x
2
=
1
2
log
e
(
√
1
+
x
2
−
1
√
1
+
x
2
+
1
)
+
C
Check
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