Physical & Chemical Equilibrium
Gas Dissociation Degree Calculation
Dissociation of a gas A
2 takes place according to the following chemical reactions. At equilibrium, the total pressure is 1 bar at 300K.
A
2(g) ⇌ 2A(g)
The standard Gibbs energy of formation of the involved substances has been provided below:
| Substance |
ΔGt°/kJ mol–1 |
| A2 |
–100.00 |
| A |
–50.832 |
The degree of dissociation of A
2(g) is given by (x × 10
–2)
1/2 where x = _________.
(Nearest integer)
[Given : R = 8 J mol
–1 K
–1, log 2 = 0.3010, log 3 = 0.48]
Assume degree of dissociation is not negligible.