Functional equations and number of solutionsHard
Functional Equation Absolute Value Summation
Let f : R → R be a function defined by f(x) = (2 + 3a)x2 + 
x + b, a ≠ 1. If f(x + y) = f(x) + f(y) + 1 – 
xy, then the value of 
is:
x + b, a ≠ 1. If f(x + y) = f(x) + f(y) + 1 – xy, then the value of is:SELECT ONE OPTION
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