First Order DE with Initial Condition (Jee Mains) | ExamDuo
Ask Doubts
Log in
First Order Differential Equations
Medium
First Order DE with Initial Condition
Let
y
=
y
(
x
)
be the solution of the differential equation
(
1
+
x
2
)
d
y
d
x
+
y
=
e
tan
−
1
x
,
y
(
1
)
=
0
. Then
y
(
0
)
is
Ask about this question
SELECT ONE OPTION
A
1
4
(
e
π
∕
2
−
1
)
B
1
2
(
1
−
e
π
∕
2
)
C
1
4
(
1
−
e
π
∕
2
)
D
1
2
(
e
π
∕
2
−
1
)
Check