Enthalpy Change Calculation

For the reaction
H2F2(g)→H2(g)+F2(g)
∆U=−59.6‌kJ‌mol−1‌ at ‌27∘C
The enthalpy change for the above reaction is (−) _______ kJ‌mol−1 [nearest integer]
Given: R=8.314JK−1mol−1