Electrochemical Cell EMF Calculation (Jee Mains)

Cell EMF and Thermodynamics

Medium

Electrochemical Cell EMF Calculation

Consider the following electrochemical cell at 298 K $Pt\left| {HSnO_2^ - \left( {aq} \right)} \right|Sn{(OH)_6}^{2 - }(aq)\left| {B{i_2}{O_3}\left( s \right)} \right|Bi\left( s \right).$
If the reaction quotient at a given time is 10⁶, then the cell EMF (E_cell) is _______× 10^–1V (Nearest integer).
Given the standard half-cell reduction potential as $E_{B{i_2}{O_3}/Bi,O{H^-}}^0 = - 0.44V$ and $E_{Sn(OH)_6^{2 - }/HSnO_2^ - ,OH}^0 = - 0.90V$

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