Law of chemical equilibrium and equilibrium constantsMedium

Dissociation Degree Expression

At temperature T, compound AB_2(g) dissociates as AB_2(g) $\rightleftharpoons$ AB_(g) + $\frac{1}{2}$ B_2(g) having degree of dissociation x (small compared to unity). The correct expression for x in terms of K_p and p is

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