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First Order Differential Equations
Medium
Differential Equation Solution Absolute Value
Let
y
=
y
(
x
)
be the solution of the differential equation
(
3
y
2
−
5
x
2
)
y
dx
+
2
x
(
x
2
−
y
2
)
d
y
=
0
such that
y
(
1
)
=
1
. then
|
(
y
(
2
)
)
3
−
12
y
(
2
)
|
is equal to:
SELECT ONE OPTION
A
32
√
2
B
64
C
16
√
2
D
32
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