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First Order Differential Equations
Medium
Definite Integral Equation and Function Evaluation
Let
x
∫
0
√
1
−
(
y
′
(
t
)
)
2
dt
=
x
∫
0
y
(
t
)
dt
,
0
≤
x
≤
3
,
y
≥
0
,
y
(
0
)
=
0
. Then at
x
=
2
,
y
+
y
+
1
is equal to :
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SELECT ONE OPTION
A
1
B
2
C
√
2
D
1
∕
2
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