DE of Circles Through Origin (Jee Mains) | ExamDuo
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Order, Degree and Formation
Medium
DE of Circles Through Origin
The differential equation of the family of circles passing the origin and having center at the line
y
=
x
is :
SELECT ONE OPTION
A
(
x
2
−
y
2
+
2
x
y
)
dx
=
(
x
2
−
y
2
+
2
x
y
)
d
y
B
(
x
2
+
y
2
+
2
x
y
)
dx
=
(
x
2
+
y
2
−
2
x
y
)
d
y
C
(
x
2
−
y
2
+
2
x
y
)
dx
=
(
x
2
−
y
2
−
2
x
y
)
d
y
D
(
x
2
+
y
2
−
2
x
y
)
dx
=
(
x
2
+
y
2
+
2
x
y
)
d
y
Check
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