Continuity at x=0 (Jee Mains) | ExamDuo
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Continuity and Differentiability
Medium
Continuity at x=0
If
f
(x) =
2 - (256 - 7x)
(1/8)
(5x + 32)
(1/5)
- 2
, (x ≠ 0) : Then for
f
to be continuous everywhere,
f
(0) is equal to
SELECT ONE OPTION
A
-1
B
1
C
2
D
None of these
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