Circle Equation Through Point (Jee Mains) | ExamDuo
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Equation & Position in Circle
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Circle Equation Through Point
The equation of the circle passing through the point (4 , 5) and having centre at (2 , 2) is :
SELECT ONE OPTION
A
x² + y² + 4x + 4y – 5 = 0
B
x² + y² – 4x – 4y – 5 = 0
C
x² + y² – 4x = 13
D
x² + y² – 4x + 4y + 5 = 0
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