Cell EMF and Thermodynamics
Cell Potential and Concentration Ratio
Consider the cell
Pt( s)|H2(g,1atm)|H+(aq,1M) Fe3+(aq),Fe2+(aq)∣Pt( s)When the potential of the cell is
0.712V at
298K, the ratio
[Fe2+]∕[Fe3+] is _______.
(Nearest integer)
Given:
Fe3++e−=Fe2+,E∘Fe3+,Fe2+∣Pt=0.771=0.06V