Cell EMF calculation (Jee Mains) | ExamDuo
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Cell EMF and Thermodynamics
Easy
Cell EMF calculation
The e.m.f. of the cell , Mg | Mg² + (1M) || Pb² (1M) | Pb is [E° (pb
2+
| Pb = - 0.14 V ,E°(Mg)
2+
| Mg) = - 2.37 V]
SELECT ONE OPTION
A
- 2.51 V
B
- 2 . 23 V
C
2.23 V
D
2.51 V.
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