Cell Constant Calculation (Jee Mains) | ExamDuo
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Electrolytic Conduction
Easy
Cell Constant Calculation
The resistance of a conductivity cell containing
0.01
M
KCl
solution at
298
K
is
1750
Ω
. If the conductivity of
0.01
M
KCl
solution at
298
K
is
0.152
×
10
−
3
S
cm
−
1
, then the cell constant of the conductivity cell is _____
×
10
−
3
cm
−
1
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