Bond Dissociation Enthalpy Calculation (JEE Mains) | ExamDuo
Enthalpy of bond dissociation, combustion and formationMedium
Bond Dissociation Enthalpy Calculation
The bond dissociation enthalpy of X2 calculated from the given data is _______ kJ mol–1. (Nearest integer)
M+X–(s)→ M+(g)+ X–(g) ΔH°lattice = 800 kJ mol–1
M(s)→ M(g) ΔH°sub = 100 kJ mol–1
M(g)→ M+(g)– + e–(g) ΔH°i = 500 kJ mol–1
X(g) + e–(g)→ X–(g) ΔH°eg = –300 kJ mol–1
M(s)+ X2(g) → M+X–(s) ΔH°f = –400 kJ mol–1
[Given : M+X– is a pure ionic compound and X forms a diatomic molecule X2 is gaseous state]