The area of the region bounded by the curves x+3y2=0x+ 3y^2 = 0x+3y2=0 and x+4y2=1x + 4y^2 = 1x+4y2=1 is equal to :
13\;\dfrac{1}{3}31
23\;\dfrac{2}{3}32
43\;\dfrac{4}{3}34
53\;\dfrac{5}{3}35