Absolute Maximum Value of Function (Jee Mains) | ExamDuo
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Application of Derivates
Medium
Absolute Maximum Value of Function
If the absolute maximum value of the function
f
(
x
)
=
(
x
2
−
2
x
+
7
)
e
(
4
x
3
−
12
x
2
−
180
x
+
31
)
in the interval
[
−
3
,
0
]
is
f
(
α
)
, then :
Ask about this question
SELECT ONE OPTION
A
α
=
0
B
α
=
−
3
C
α
∈
(
−
1
,
0
)
D
α
∈
(
−
3
,
−
1
]
Check