Let f(x)=x(2x−1)f(x)=\frac{x}{(2x-1)}f(x)=(2x−1)x and g(x)=x(x−1)g(x)=\frac{x}{(x-1)}g(x)=(x−1)x. Then the domain of the function h(x)=f(g(x))+g(f(x))h(x)=f(g(x))+g(f(x))h(x)=f(g(x))+g(f(x)) is all real numbers except
−1,12,and 1-1,\frac{1}{2}, \text{and} 1−1,21,and 1
12,1,and 32\frac{1}{2}, 1, \text{and} \frac{3}{2}21,1,and 23
−12,12, and 1-\frac{1}{2},\frac{1}{2}, \text{and} 1−21,21, and 1
12,and 1\frac{1}{2}, \text{and} 121,and 1