If 1212x×424x+12×52y=84z×2012x×2433x−612^{12x}\times 4^{24x+12}\times 5^{2y}=8^{4z}\times 20 ^{12x} \times 243^{3x-6}1212x×424x+12×52y=84z×2012x×2433x−6, where x , y and z arenatural numbers, then x+y+zx + y + zx+y+z equals